Question

44.
If the forebearing of a line AB is 35º and
that of line BC. 15°, then the included
angle between the lines is
a) 20°
b) 50°
c) 160°
d) 230°​

Answer 1

Answer:

The included angle between the lines is 35 – 15 = $20^\circ$

Given:

If the fore bearing of a line AB is $35^\circ$ and that of line BC is  $15^\circ$,  

To find:

Then the included angle between the lines is

Solution:

Consider AC is the base line of the triangle.

Given AB = $35^\circ$,

Hence 180 – 35 = $145^\circ$

BC = $15^\circ$,

the included angle between the lines is 35 – 15 = $20^\circ$

Result:

The included angle between the lines is 35 – 15 = $20^\circ$

Answer 2

Step-by-step explanation:

35°-15°=20°

180°-20°=160°