Question

44. In a mixture ratio of first and second liquid is 2 : 3
and in another mixture ratio of those two liquids is 5 : 4.
Ratio in which the two mixtures be mixed so that
quantity of two liquid in the new mixture be equal is
(A) 2:5
(B) 3:7
(C) 5:9
(D) 9:11​

Answer 1

Answer:

C) 5:9

Step-by-step explanation:

Let the total amount in 1st container be 5a

and part of 1st liquid = 2a

and part of 2nd liquid = 3a

Let the total amount in 2nd container be 9b

and part of 1st liquid = 5b

and part of 2nd liquid = 4b

And part of 1st liquid in mixture = 2a + 5b

and part of 2nd liquid in mixture = 3a + 4b

so according to question,

$\frac{amt \: of \: 1st \: liquid}{amt \: of \: 2nd \: liquid} = \frac{1}{1}$

so, 2a + 5b = 3a + 4b

=> a = b

So ,

$\frac{amt \: of \: a \: liq}{amt \: of \: b \: liq} = \frac{5a}{9b}$

We know a=b

so, ratio is 5:9.