Question

44. Kapil travels 30m from a point a towards north and from the south point. Sachin travels 40m towards east. How

Answer 1

Kapil travels 30m from a point A towards north and from the south point Sachin travels 40m towards east . How far are the two friends from each other now?

Kapil traveled northwards and Sachin traveled eastwards

⇒ The distance between them is the length of the hypotenuse between them

⇒ see attachment

Find the distance:

a² + b² = c²

30² + 40² =c²

c² = 900 + 1600

c² = 2500

c = √2500

c = 50 m

Answer: They are 50 m away from each other.

Answer 2

In ∆ABC, by Pythagoras theorem:-


${ac }^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {30}^{2} + {40}^{2} \\ {ac}^{2} = 900 + 1600 \\ {ac}^{2} = 2500 \\ ac = \sqrt{2500} \\ ac = 50$