Question

44. Ratio of Cv, and Cy of a gas X is 1.4. The
number of atoms of the gas X present in
11.2 litres of it at NTP will be
(a) 6.02 x 1023
(b) 1.2 x 1023
(c) 3.01 X 1023
(d) 2.01 x 1023
​

Answer 1

Answer:

(c) 3.01 X 1023

Explanation:

22.4 liters NTP = 6.02 x 1023

11.2 liters NTP= (6.02 x 1023 ×11.2)/22.4

=3.01 X 1023