Question

44) Rs. 10,000 is invested at annual rate of
interest of 10%. The amount after two years
at annual compounding is
(M 19, MTP-2) (MQB)
a) Rs. 21100
b) Rs. 12100
C) Rs. 12110
d) None of these​

Answer 1

➤ Given :-

Principle (P) :- ₹ 10000

Rate of interest (R) :- 10%

Time (T) :- 2 years

➤ To Find :-

Annually compounding Interest.............

➤ Formula :-

$\bf \orange{\bigstar \: {\underline {\underline{ P \times R \times T \div 100 + P}}}}$

➤ Solution :-

$\dashrightarrow \sf \frac{10000 \times 10 \times 2}{100} + 10000$

$\dashrightarrow \sf \frac{ \cancel{10000} \times 10 \times 2}{ \cancel{100}} = 100 \times 10 \times 2$

$\dashrightarrow \sf2000 + 10000$

$\dashrightarrow \sf12000$

$\Huge\therefore$The amount compounded annually is ₹ 12000.