Physics, asked by abhiayadav7748, 3 months ago

44. Suppose the spheres A and B in Q. 43 have
identical sizes. A third sphere of the same size
but uncharged is brought in contact with the
and finally removed from both. What is the new
first, then brought in contact with the second
force of repulsion between and B ? NCERT, (3M
distance bet
uunit of caesium​

Answers

Answered by momo5392
0

Answer:

A third sphere of the same size but uncharged is brought in contact with the first, then brought in contact with the second, and finally removed from both. .

Hence, charge on each of the spheres, C and B, is 3q/4

Explanation

Distance between the spheres, A and B, r = 0.5 m

Initially, the charge on each sphere, q = 6.5 × 10 −7 C

When sphere A is touched with an uncharged sphere C, q/2 amount of charge from A will transfer to sphere C. Hence, charge on each of the spheres, A and C, is q/2.

When sphere C with charge q/2 is brought in contact with sphere B with charge q, total charges on the system will divide into two equal halves given as,

1/2 (q + q/2) = 3q/4

Hence, charge on each of the spheres, C and B, is 3q/4.

Similar questions