Question

44. The distance covered by a body in one complete vibration is 20cm. What is the amplitude of body
a. 10 cm
b. 5 cm
c. 15 cm
d. 7.5 cm

Answer 1

Answer: b. 5 cm

Explanation: take the example of simple vibration: A..........B*..........C here,* is the body and ............ indicates its path. initially it is at the mid point of the dots. Assume that initially the body is at the mid point of the path shown. then, amplitude= BC given that total distance covered in one complete vibration is 20 cm path: B to C, then C to B then, B to A and finally A to B so, BC+CB+BA+AB = 20, as all of them are equal, so amplitude comes 5 cm

Answer 2

Given:

Distance covered in one vibration is 20 cm.

To find:

Amplitude of body?

Calculation:

• Let's assume that the object started from its mean position. Then it went to its extreme position followed by return to its mean position.

• Then , it follows the same cycle on the opposite extremity and completes one vibration.

• So, 4 amplitudes have been covered.

$4 \times A = total \: distance$

$\implies \: 4A = 20$

$\implies \: A = 5 \: cm$

So, amplitude is 5 cm.