Question

44. The equation of normal from (x, y) to the
circle x2 + y2 = a? is-
(A) xy1 = yxi (B) xy + yx = 0
(C) XX, + yy=0 (D) None of these​

Answer 1

Step-by-step explanation:

ln(x+y)=yln(x)

x+y1.(1+dxdy)=xy+dxdy.ln(x)

Now y=0 and dxdy=m we get 

x1+m=m.ln(x)

Now x=1 when y=0

Hence

1+m=0

m=−1

Slope of normal =1.

Hence

x−1y−0=1

y=x−1.