Question

`44. The length of each side of a square held field is 50 m. At one of its vertices a cow is tethered by a 3 m long rope. Find the area of the region of the field in Which the Cow can graze. ( π= 3.14) `​

Answer 1

Answer:

7.065m²

Step-by-step explanation:

$\pi \times {3}^{2} \div 4$

Area of a circle is

$\pi \times {r}^{2}$

since, it is given to be a square shaped field and the cow is tied to a 3m long rope at one end it can go to maximum of 3m distance in any direction inside the field. which will be an arc of 90 degrees which is a quarter of a circle. so area of that sector with this arc will be one fourth of the area of the circle with 3m radius.

hence the area the field cow can Graze is

$\pi \times {r}^{2} \div 4 = 3.14 \times {3}^{2} \div 4 = 3.14 \times 9 \div 4$