44) The nth term of the arithmetic progression 4, 2,0,-2.... is
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9th term is -14.
Here, a=2, d= 0-2 = -2
t(n) = a+(n-1)d
t(9) = 2+(9-1)(-2)
t(9) = 2+(8)(-2)
t(9) = 2-16
t(9) = -14
Thus, 9th is -14.
Answered by
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Answer:
The nth term of the arithmetic progression 4,2,0,-2... is t(n) = 6 - 2n.
Step-by-step explanation:
- A sequence in which the difference of two consecutive terms is constant is called Arithmetic progression.
- a , a + d , a + 2d , .... is an arithmetic progression, where first term = a ; and common difference = d.
- The nth term, t(n) of an arithmetic progression with first term as a and common difference as d is given by:
- Here, first term, a = 4
- Common difference, d = t(n+1) - t(n)
= 2 - 4 = -2 .
- The nth term of the given arithmetic progression is given by:
- Hence, nth term of the given AP is 6 - 2n.
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