Math, asked by mulgundfayaz, 1 year ago


44) The nth term of the arithmetic progression 4, 2,0,-2.... is​

Answers

Answered by Hiteshbehera74
2

9th term is -14.

Here, a=2, d= 0-2 = -2

t(n) = a+(n-1)d

t(9) = 2+(9-1)(-2)

t(9) = 2+(8)(-2)

t(9) = 2-16

t(9) = -14

Thus, 9th is -14.

Answered by abhijattiwari1215
1

Answer:

The nth term of the arithmetic progression 4,2,0,-2... is t(n) = 6 - 2n.

Step-by-step explanation:

  • A sequence in which the difference of two consecutive terms is constant is called Arithmetic progression.
  • a , a + d , a + 2d , .... is an arithmetic progression, where first term = a ; and common difference = d.
  • The nth term, t(n) of an arithmetic progression with first term as a and common difference as d is given by:

t(n) = a + (n - 1)d

  • Here, first term, a = 4
  • Common difference, d = t(n+1) - t(n)

= 2 - 4 = -2 .

  • The nth term of the given arithmetic progression is given by:

t(n) = 4 + (n - 1)( - 2) \\ t(n) = 4 - 2n + 2 \\ t(n) = 6 - 2n

  • Hence, nth term of the given AP is 6 - 2n.
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