44.The number of terms in the A.P.2,5,8,..-...,59 is
(a)12 (b) 19 (c) 20
(d) 25
Answers
Answer:
Step-by-step explanation:
Here a=2 , d= 3 and An=59
We know that,
An=a+(n-1)d
Now we put the values of a,Anand d
59=2+(n-1)3
59-2=(n-1)3
57=(n-1)3
57/3=(n-1)
19=(n-1)
19+1=n
20=n
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Answer:
The number of terms in the A.P.2,5,8,..-...,59 is 20.
Step-by-step explanation:
Step : 1 Here a=2 , d= 3 and An=59
We know that,
An=a+(n-1)d
Now we put the values of a,Anand d
59=2+(n-1)3
59-2=(n-1)3
57=(n-1)3
57/3=(n-1)
19=(n-1)
19+1=n
20=n
Step : 2 We will immediately apply the AP formula, l - (n-1)d, to obtain the 20th term from the final term of the provided arithmetic sequence because we are aware that the given series is in AP. Here, n is the specified number of terms, l is the final term, and d is the common difference.
Step : 3 The formula is "rArr T (25) = a + (25-1) d" '(-5) + (24 xx (5)/(2)) = -5 + 60 = 55.' 25th term = 55 as a result. Experts' step-by-step guidance will help you clear up any doubts and get exceptional test results.
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