Question

44.The number of terms in the A.P.2,5,8,..-...,59 is
(a)12 (b) 19 (c) 20
(d) 25​

Answer 1

Answer:

Step-by-step explanation:

Here a=2 , d= 3 and An=59

We know that,

An=a+(n-1)d

Now we put the values of a,Anand d

59=2+(n-1)3

59-2=(n-1)3

57=(n-1)3

57/3=(n-1)

19=(n-1)

19+1=n

20=n

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Answer 2

Answer:

The number of terms in the A.P.2,5,8,..-...,59 is 20.

Step-by-step explanation:

Step : 1 Here a=2 , d= 3 and An=59

We know that,

An=a+(n-1)d

Now we put the values of a,Anand d

59=2+(n-1)3

59-2=(n-1)3

57=(n-1)3

57/3=(n-1)

19=(n-1)

19+1=n

20=n

Step : 2  We will immediately apply the AP formula, l - (n-1)d, to obtain the 20th term from the final term of the provided arithmetic sequence because we are aware that the given series is in AP. Here, n is the specified number of terms, l is the final term, and d is the common difference.

Step : 3   The formula is "rArr T (25) = a + (25-1) d" '(-5) + (24 xx (5)/(2)) = -5 + 60 = 55.' 25th term = 55 as a result. Experts' step-by-step guidance will help you clear up any doubts and get exceptional test results.

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