Question

4458=11,2232=1,5678=14,7921=?

Answer 1

Answer:

7921=11

Step-by-step explanation:

4458=(4*4)+ (5*8) = 56=5+6=11

2232=(2*2)+(3*2)=10=1+0=1

5678=(5*6)+(7*8)=86=8+6=14

plzzz mark as barinliests

Answer 2

•Given:-

4458=11,2232=1,5678=14

•To find:-

7921=?

•solution:-

according to the series

the format is like

(A×B)+(C×D)= EF = E+F= FINAL ANS

[where the number is ABCD]

where A is the first element of that particular number

B is the second element of that perticular number

C is third element of that particular number

D the fourth element of that particular number

and according to the format

4458=(4×4)+ (5×8) = 56=5+6=11

2232=(2×2)+(3×2)=10=1+0=1

5678=(5×6)+(7×8)=86=8+6=14

SO

7921=(7×9)+(2×1) = 66= 6+6= 12

So the final series is

4458=11,2232=1,5678=14,7921=12