Math, asked by neelkale, 9 months ago

44x2-x-3 factories it​

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Answers

Answered by Anonymous
23

Answer:

we have,

=> 44x^2 - x - 3

=> 44x^2 - 12x + 11x - 3

=> 4x(11x-3) + (11x-3)

=> (11x-3)(4x+1)

thus the factorised form of

44x^2-x-3 is (11x-3)(4x+1).

note;

if we want to find the zeros of the given polynomial, then we would equate its factors equal to zero.

here , we have the factorised form of polynomial as: (11x-3)(4x+1)

thus to get it's zeros,we have,

=> (11x-3)(4x+1)=0

ie, either (11x-3)=0 or (4x+1)=0

thus, the zeros of the polynomial would be: x=3/11 or -1/4

Answered by gisellefarrow
4

Answer:

(11x-3) (4x-1) Are the factors

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