45*[15+(-11) ]=(45*15) +[45*(-11) ]
Answers
Step-by-step explanation:
SOLUTION:
i) 15,45,40,120
we have 15,45,40,120
ratio of 15 to 45=\frac{15}{45}=\frac{15\div15}{45\div15}=\frac{1}{3}=1:3
45
15
=
45÷15
15÷15
=
3
1
=1:3
[HCF OF 40 and 15, 45 is 15]
ratio of 40 to 120=\frac{40}{120}=\frac{40\div40}{120\div40}=\frac{1}{3}=1:3
120
40
=
120÷40
40÷40
=
3
1
=1:3
[HCF of 40 and 120 is 40]
here, 15:4=40:120=1:3
ii) 33, 121,9,96
we have 33,121,9,96
ratio of 33 to121 = \frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}
121
33
=
121÷11
33÷11
=
11
3
ratio of 9 and 96= \frac{9}{96}=\frac{9\div3}{96\div3}=\frac{3}{32}
96
9
=
96÷3
9÷3
=
32
3
[HCF of 9 and 96 is 3]
here, 3:11\ne3:323:11
=3:32
i.e\ 33:121\ne9:96i.e 33:121
=9:96
therefore, 31,121,9 and 96 are not in proportion.
iii) 24,28,36,48
ratio of 24 and 28 is \frac{24}{28}=\frac{24\div4}{28\div4}=\frac{6}{7}=6:7
28
24
=
28÷4
24÷4
=
7
6
=6:7
[HCF of 36 and 48 is 12]