45 -[28-{37-(15-x)}]= 58
Answers
Answered by
1
45 -[28-{37-(15-x)}]=58
=> -[28-{37-(15-x)}] =58-45 =13
=> 28-{37-(15-x)} = -13
=> -{37-(15-x)} = -41
=> {37-(15-x)} = 41
=> 37-(15-x) =41
=> -(15-x) = 4
=> x-15 =4
Hence , x =19
=> -[28-{37-(15-x)}] =58-45 =13
=> 28-{37-(15-x)} = -13
=> -{37-(15-x)} = -41
=> {37-(15-x)} = 41
=> 37-(15-x) =41
=> -(15-x) = 4
=> x-15 =4
Hence , x =19
Answered by
7
hey, here is your answer...
45-[28-{37-(15-x)}] = 58
45-[28-{37-15+x}] = 58
45-[28-{22+x}] = 58
45-[28-22-x] = 58
45-[6-x] =58
45-6+x =58
39+x = 58
x = 58-39...
x = 19.........
hope this helps you...
thank you...
plzz mark my answer as brainliest....
45-[28-{37-(15-x)}] = 58
45-[28-{37-15+x}] = 58
45-[28-{22+x}] = 58
45-[28-22-x] = 58
45-[6-x] =58
45-6+x =58
39+x = 58
x = 58-39...
x = 19.........
hope this helps you...
thank you...
plzz mark my answer as brainliest....
krish920:
Pehle khushiMidha ko fasa rha tha ab is bholi bhali ladki ko fasa rha h
Sorry to say this as am younger than you, but why do u need my no. ?? go to the hell..I dont like this type of attitude... you r crossing ur limits brother...
Shresta he is a playboy
He talk to new girl every hour
A girl name is KhushiMidha... He was approaching her
Tera sach sabke samne launga
Hindi bol be
Similar questions