Question

45-[28-{37-(15-x)}]=58, then the value of x is

Answer 1

Step-by-step explanation:

$45-[28-{37-(15-x)}]=58$

• First we need to simplify it.

${:}\longrightarrow$$45-[28-{37-15+x}]=58$

${:}\longrightarrow$$45-[28-37+15-x ]$

${:}\longrightarrow$$45-[6-x]=58$

${:}\longrightarrow$$45-6+x=58$

• Now interchange both sides and get x

${:}\longrightarrow$$39+x=58$

${:}\longrightarrow$$x=58-39$

$\therefore$${\underline{\boxed{\bf {x=19}}}}$

Answer 2

Answer:

28

Step-by-step explanation:

45-[28-{37-15+x}]=58

45-[28-{22+x}]=58

45-[28-23-x]=58

45-[5-x]=58

45-5+x=58

30+x=58

x=58-30

x=28