Question

45÷[29+4 {5+(9-2)3)}]using BODMAS​

Answer 1

Answer:

45÷[29+4{5+(9-2)3}]

Using BODMAS,

We shall solve the small bracket first,

=45÷[29+4{5+(7)3}]

Now middle bracket is to be solved,

=45÷[29+4{5+21}]

=45÷[29+4×26]

=45÷[29+104]

Now we will solve the big bracket,

=45÷131

$\huge{ = \frac{45}{131} }$

Answer 2

Answer:

45÷[29+4 {5+(9-2)3)}]

Step-by-step explanation:

45/[33{5+(7x3)

=45/33(5+21)

=45/33x26

=45 /858

= 858 / 45