Question

45,39,x,y,21 are in an AP. what are the values of x and y .

Answer 1

Consider these are the first 5 terms of the AP.

$d = 39 - 45 = - 6 \\ \\ \\ T_3 = T_2 + d \\ \\ = 39 + (- 6) = 39 - 6 = 33 = x \\ \\ \\ T_4 = T_5 - d \\ \\ = 21 - (- 6) = 21 + 6 = 27 = y \\ \\ \\ \\ \therefore x = 33; y = 27$

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Answer 2

Answer:

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