Math, asked by VerifiedPerson, 5 months ago

45) + (908) + (-76)
What is the sum of:
(i) the largest 4-digit positive integer and
the smallest 3-digit negative integer?
(ii) the largest 5-digit even positive integer
and the smallest 5-digit odd negative
integer?​

Answers

Answered by sunitamanjeetsuthar
3

answer

Step-by-step explanation:

the smallest five digit number is 10000

the greatest five digit number is 99999

Attachments:
Answered by rishi20284
20

Step by step explanation

  • 45 + 908 + (-76)
  • 953 - 76
  • 877

(i) Largest 4 digit positive integer is 9999

Smallest 3 digit negative integer is-999

  • 9999 + (-999)
  • 9999 - 999
  • 9000

So, the sum of largest 4 digit positive integer and smallest 3 digit integer is

9000

(ii) Largest 5 digit even positive integer

is 99998

Smallest 5 digit odd negative integer

is 10001

  • 99998 + 10001
  • 109999

So, the sum of largest 5 digit even positive integer and smallest 5 digit odd

negative integer is 109999

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