45) + (908) + (-76)
What is the sum of:
(i) the largest 4-digit positive integer and
the smallest 3-digit negative integer?
(ii) the largest 5-digit even positive integer
and the smallest 5-digit odd negative
integer?
Answers
Answered by
3
answer
Step-by-step explanation:
the smallest five digit number is 10000
the greatest five digit number is 99999
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Answered by
20
Step by step explanation
- 45 + 908 + (-76)
- 953 - 76
- 877
(i) Largest 4 digit positive integer is 9999
Smallest 3 digit negative integer is-999
- 9999 + (-999)
- 9999 - 999
- 9000
So, the sum of largest 4 digit positive integer and smallest 3 digit integer is
9000
(ii) Largest 5 digit even positive integer
is 99998
Smallest 5 digit odd negative integer
is 10001
- 99998 + 10001
- 109999
So, the sum of largest 5 digit even positive integer and smallest 5 digit odd
negative integer is 109999
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