45.
A alonecan do a cortain job in 25 days which B alone 'can do in 20 days. A started the work
and was joined by B after 10 days. The work lasted for:
(A) 12 days
(C) 15 days)
(B) 14 days
5 6 days
Answers
Answered by
0
Answer:
Step-by-step explanation:
Work done by A in l0 days = (1/25) *10 = 2/5
Remaining work = 1 - (2/5) = 3/5
(A+B)s 1 days work = (1/25) + (1/20) = 9/100
9/100 work is done by them in 1 day.
hence 3/5 work will be done by them in (3/5)*(100/9)
= 20/3days.
Total time taken = (10 + 20/3) = 16*(2/3) days
Answered by
0
Answer:
D) 6 days
total work for A = 25 days
total work for B = 20 days
10 days later,
total work for A = 15 days
total work for B = 10 days
if they work together then let x be the number of days they take
therefore,
1/15 + 1/10 = 1/x
25/150 = 1/x
x = 150/25
x = 6 days
Step-by-step explanation:
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