Question

45) A body starting with an initial velocity of 5 m/s, moves with a uniform acceleration of
2 m/s2 After some time it attains a velocity of 13 m/s. Find the distance covered by body
during this period.​

Answer 1

Answer:

Given -

u = 5m/s

v = 13m/s

a = 2m/s^2

s =?

v^2 = u^2 + 2as

13^2 = 5^2 + 2 × 2 × s

169 = 25 + 4s

169 - 25 = 4s

4s = 144

s = 144/4

s = 36 m

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Answer 2

Explanation:

as initial velocity is 5m/s and final velocity is 13m/s. also acceleration is2m/s^2

so use the formula v^2 -u^2 =2as