Question

т
45. A scooter is travelling on a straight road with a speed of 30 kmh behind the scooter, there is a ca
travelling at a speed of 45 kmh. When the distance between them is 7.5 km the car is
acceleration of 15 kmh. After what distance and time with the car catch the scooter ?
​

Answer 1

Explanation:

ANSWER

For B to catch A both will have to reach the same point in same time.

Let that distance be x . B will have to cover x+2kmin the same time.

For B equation will be

x=60km/hr×t

t=

60

x

hr

For A equation will be

x+2=70km/hr×

60

x

hr+

2

1

×−20km/hr

2

×(

60

x

)

2

x

2

−60x+720=0

The solution for the above equation using the quadratic formula will be

x=30(1±

2

)km

As we have to find the shortest distance, that distance will be

x=30(1−

2

)km