Chemistry, asked by shouryasugla, 10 months ago

45. For strong acid strong base neutralisation energy
for 1 mole H2O formation is -57.1 kJ. If 0.25 mole
of strong monoprotic acid is reacted with 0.5 mole
of strong base then enthalpy of neutralisation is
(1) -(0.25 * 57.1) (2) 0.5 * 57.1
(3) 57.1
(4) -(0.5 ~ 57.1)​

Answers

Answered by sidddddhesh
5

Answer : option 1

Please refer to image

Also do note, for similar problems , if the amount of Base is lesser than the amount of acid , make sure you use the concentration of base to multiply with the enthalpy , because in that case , the base will become the limiting reagent , anyhow in our question the acid is the limiting reagent since it's concentration = 0.25 M < [base] = 0.5M

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