.45 g of acid was exactly neutralized by 20ml of 0.5N NaOH . Basicity of acid is.
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Hello Dear,
◆ Answer -
Basicity = 2
◆ Explaination -
# Given -
W1 = 0.45 g
M1 = 90 g
V2 = 20 ml = 0.02 L
N2 = 0.5 N
# Solution -
For acid to be neutralized by NaOH,
N1.V1 = N2.V2
W1/(E1.V1) × V1 = N2.V2
W1/E1 = N2.V2
E1 = W1/(N2.V2)
E1 = 0.45 / (0.5 × 0.02)
E1 = 45 g
Basicity of the acid is given by -
Basicity = M1/E1
Basicity = 90 / 45
Basicity = 2
Therefore, basicity of the acid is 2.
Thanks dear...
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