Question

45 g of water at 50°C in a beaker is cooled when 50 g of copper at 18°C is added to it. The contents are stirred till a final constant temperature is reached. Calculate the final temperature

Answer 1

Heat gained by copper = m × C × θ
                                     = 50 × 0. 39 × (T − 18)

Heat lost by water = 45 × 4. 2 × (50 − T)

 Heat lost = Heat gained

 45 × 4. 2 × (50 − T) = 50 × 0. 39 × (T − 18)

9450 − 189 T = 19. 5 T − 351
 208. 5 T = 9801
Or T = 47°C (Approx) 

 So the final temperature is 47°C (Approx)


i hope it will help you
regards

Answer 2

here is the answer babe