Question

45.
If the initial pressure of N, and H, mixture in a
closed apparatus is 100 atm. At equilibrium 20%
of the mixture reacts then total pressure at the
same temperature would be
(1) 100 (2) 90 (3) 85 (4) 80​

Answer 1

Answer:90(please give branliest)

Explanation:N2+3H2=2NH3;

As we know

N2+H2=100 atm.

Let

Partial pressure of N2 &H2 be

= pN2 +p3H2

=P +3P

=4P

Therefore,

4P=100

P=25

As we know,20% mixture react means α=2. As per the Formula,

α=x÷P;

x=5

So, N2+3H2=2NH3

Intially, The pressures of N2, 3H2 and 2NH3 would be 25, (3×25) and (2×25) i.e., 25,75 and 50 atm respectively.

At Equilibrium, the pressures would be (25-x), (75-3x), 2x

i.e.,

(25-5) ,(75-15), {2(5)} = 20,60,10 atm resp.

P=20+60+10

P=90 atm