Question

45. In the following figure, AD= 5.6 cm, AE = (x + 1)
cm, AB = 8.4 cm and EC = (x - 1) cm, find AC.
Given that DE || BC.
Plz give answer fast
I will mark as brainliest ​

Answer 1

Answer:

as DE || BC

then,

ADE = ABC

and

AED = ACB

so,

triangle ADE is similar to triangle ABC

AC = (x+1)+(x-1) = 2x

AD/AB = AE/AC

5.6/8.4 = (x+1)/2x

8.4(x+1) = 5.6(2x)

8.4x + 8.4 = 11.2x

11.2x - 8.4x = 8.4

2.8x = 8.4

x = 8.4/2.8 = 84/28 = 21/7 = 3

AC = 2x = 2 × 3 = 6