45.) In triangle ABC, what is the distance between the
midpoint of BC and the foot of the perpendicular from
A to BC, if the lengths BC, CA and AB are 5 cm, 7 cm
and 6 cm respectively? (in cm)
Answers
Answered by
0
Answer:
Step-by-step explanation:
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Answered by
0
Answer: hop it works
Step-by-step explanation: Using pythagoras theorem,
c
2
=BH
2
+AB
2
→c
2
=(
2
a
−HM)+AH
2
b
2
=CH
2
+AH
2
→b
2
=(
2
a
−HM)+AH
2
now we find HM (the distance between the middle point of BC and the foot of the perpendicular from A) using the above equations
b
2
−c
2
→(
2
a
−HM)+AH
2
−((
2
a
−HM)+AH
2
)→
4
a
2
+2
2
a
.HM+HM
2
+AH
2
−(
4
a
2
+2
2
a
.HM+HM
2
+AH
2
)→2a.HM
→
HM=
2a
b
2
−c
2
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