Math, asked by rawalchanchal633, 1 month ago

45. निम्नलिखित व्यंजक का (पूर्ण संख्या में) निकटतम मान ज्ञात कीजिए: 349 x 51 +(632-31) (A) 17522 (B) 17520 (C) 17821 (D) 17521 कच्चे कार्य​

Answers

Answered by amitnrw
3

Given : 349 x 51 +(632÷31)

To Find : (पूर्ण संख्या में) निकटतम मान

Solution:

349 x 51 +(632÷31)

349 x 51 = 350 * 50  = 17500

(632÷31) = 600 / 30  = 20  

Hence 349 x 51 +(632÷31)

= 17500 + 20

= 17520

Hence (पूर्ण संख्या में) निकटतम मान = 17520

Estimated value of  349 x 51 +(632÷31) =  17520

Exact calculation :

632÷31

= (620 + 12) ÷31

=(620÷31 )  + (12  ÷31)

= 20  +  (12  ÷31)

≈ 20  as  12  ÷31 < 0.5

349 x 51

= (350 - 1) * (50 + 1)

= 350 * 50  - 50 + 350 - 1

= 17500 + 299

= 17799

17799 + 20

= 17,819

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