Question

45% of first number is equal to 60% of second number. If average of both the numbers is 10 less than the first
number, then find 80% of second number?
1. 64
2.40
3.48
4 56

Answer 1

Answer:

let x and y be the first and second numbers respectively.

Step-by-step explanation:

Then, as per given in the question we have ,

$45\times\frac{x}{100} = 60\times\frac{y}{100}$

on solving we get , 3x = 4y ---------------------------- (i)

average of the numbers is less than 10 ----------------------- (given )

i.e.  $\frac{x + y}{2} = x -10$

     x- y = 20 -----------------------(ii)

from (i) and (ii) we get ,

y = 60

then 80 % of second number that is ' y ' = 48

Answer 2

From the given question the correct answer is:

3.48 is  80% of second number.

Solution:

Then, as per given in the question we have ,

45×=60×

on solving we get , 3x = 4y ---------------------------- (i)

average of the numbers is less than 10 ----------------------- (given )

= x-10

x- y = 20 -----------------------(ii)

from (i) and (ii) we get ,

y = 60

then 80 % of second number that is ' y ' = 48