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The density of a linear rod of length L varies as
d=A+Bx where x is the distance from the left end.Locate the centre of mass.
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Hello mate here is your answer.
total mass = density * length
that is
dm = lamda * dx
dm = (x+2)dx
integrating both sides,
we get,
m = x^2/2 + 2x
= l^2/2 + 2l
put l = 3 meter.
m = 9/2 + 6 = 21/2 m that is approx. 10.5 m
Hope it helps you.
total mass = density * length
that is
dm = lamda * dx
dm = (x+2)dx
integrating both sides,
we get,
m = x^2/2 + 2x
= l^2/2 + 2l
put l = 3 meter.
m = 9/2 + 6 = 21/2 m that is approx. 10.5 m
Hope it helps you.
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