Math, asked by domanicreji96, 27 days ago

45 roses 65 carnations and 50 tulips are to be used to prepare identical flowers arrangements for a wedding ceremony.what is the maximum number of such arrangement if no flowers are to be left out

Answers

Answered by nimeshbhaskar2005
4

Step-by-step explanation:

Since no flowers are to be left out, then the number of bouquets must be a factor of 45,65 and 50.

45 = 5*3*3

65 = 5*13

50 = 5*5*2

HCF(45, 65, 50) = 5

Therefore, 5 arrangements are possible.

Answered by harshpandayoir
1

Answer:

Since no flowers are to be left out, then the number of bouquets must be a factor of 45,65 and 50. Therefore, 5 arrangements are possible.

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