Question

45. Sudhir has coins of the denomination of . 1, 50 p
and 25 p in the ratio of 12:10:7. The total worth
of the coins he has is 112.5. Find the number of
25 p coins that Sudhir has
(a) 48
(b) 72
(c) 60
(d) 42​

Answer 1

Answer:

(d) 42 is the answer because 12x + 10x + 7x = 112.5 . 29x = 112.5. 10x = 42

Answer 2

Answer:

Number of 25 p coins = 42

Option (d) is correct answer

Step-by-step explanation:

Given data

Sudhir has coins of denominations 1 ₹, 50 p and 25 p

the ratios of the coins = 12 : 10 : 7

the worth of the total coins = 112.5

here we need to find number of 25 p coins that Sudhir has

let 12x, 10x and 7x are be the number of coins of  1 ₹, 50 p and 25 p respectively    [ ∵ they are in ratio 12 : 10 : 7 ]  

⇒ total worth of the coins

= 12x(1) + 10x (1/2) + 7x (1/4)  = 112.5   [∵50 p = 1/2 rupee,  25 p = 1/4 rupee ]

= $\frac{12X(4)+10X(2)+7X }{4} = 112.5$

= 48x + 20x + 7x  = 450

=  75x = 450

=   x = 6  

⇒ number of 25 p coins = 7x =7(6) = 42

                  Option (d) is correct answer