Question

45. The kinetic energies of an electron and proton are same. The ratio of de-Broglie wavelengths associated
with them will be
(A) 1.1836
(B) (1836: 1
(C) 1836:1
(D) (1836)2:1​

Answer 1

Answer:

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We know that de-Broglie wavelength

λ

of a particle of mass

m

and momentum

p

is given by the expression

λ

=

h

p

where

h

is Planck's Constant.

Kinetic energy is given as

K

E

=

p

2

2

m

In terms of de-Broglie wavelength

λ

K

E

=

(

h

λ

)

2

2

m

⇒

K

E

=

h

2

2

m

λ

2

Ratio of kinetic energies of electron and proton

K

E

e

K

E

p

=

(

h

2

2

m

λ

2

)

e

(

h

2

2

m

λ

2

)

p

When both have same wavelength above reduces to

K

E

e

K

E

p

=

m

p

m

e

Answer 2

Answer:

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