Question

450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited . calculate the composition of resulting mixture .

Answer 1

Hello beautiful..!!

It is given that,

2NO (g) + O2 (g) -------> 2NO2(g)

2vol : 1 vol ------> 2vol ( according to lussac's law)

•To calculate amount of unused NO

NO : O2

2 : 1

X : 200

Implies X = 400 cm^3.

Total given nitrogen monoxide is 450 therefore 450 - 400 = 50cm^3.

• To calculate amount of NO2 formed :

O2 : NO2

1 : 2

200 : X1

Implies X1 = 400cm^3.

Therefore unused NO = 50cm^3 and amount of NO2 formed = 400cm^3

Therefore the total mixture composition is 450 cm^3.

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Hope it is useful...!!