450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited . calculate the composition of resulting mixture .
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Hello beautiful..!!
It is given that,
2NO (g) + O2 (g) -------> 2NO2(g)
2vol : 1 vol ------> 2vol ( according to lussac's law)
•To calculate amount of unused NO
NO : O2
2 : 1
X : 200
Implies X = 400 cm^3.
Total given nitrogen monoxide is 450 therefore 450 - 400 = 50cm^3.
• To calculate amount of NO2 formed :
O2 : NO2
1 : 2
200 : X1
Implies X1 = 400cm^3.
Therefore unused NO = 50cm^3 and amount of NO2 formed = 400cm^3
Therefore the total mixture composition is 450 cm^3.
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Hope it is useful...!!
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