Question

θ = 45° के लिए परास,अधिकतम ऊंचाई, उड्डयन काल ज्ञात कीजिए ।
Class 11 th NCERT​

Answer 1

Answer:

if angle ofsc3nt is 45 degree .the projectile is maximum.

Explanation:

projectile motion =time of ascent +time of decent

2sin*/g