45g of ethylene glycol is mixed with 600g of water.calculate the freezing point depression and the freezing point of the solution?
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45 g of ethylene glycol is mixed with 600 g of water. What is the freezing point of the solution? kf=1. 86 K kg mol−1.
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Answer:
270.90K
Explanation:
45 g of ethylene glycol is mixed with 600 g of water.
Molar mass of ethylene glycol =62 g/mol
45 g ethylene glycol = 45 / 62 = 0.726 moles.
600 g water =0.600 kg
Molality (m)= 0.726 / 0.600 = 1.21 m
The depression in the freezing point ΔTf = Kf m
=1.86×1.21=2.25K
The freezing point of pure water =273.15 K.
Freezing point of solution =273.15+2.25=270.90K
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