Math, asked by chitranshhealthcare, 2 months ago

45x⁴y+6x³y²-72x²y⁴ factories it urgent​

Answers

Answered by utsavdasgupta9
5

Answer:

Step1)Take 3x²y as common

(3x²y)(15x²+2xy-24y²)

Step2) Now factorize the second term=(15x²+2xy-24y²)

Step3)To factorize this term, simply explit the middle part '2xy' into '20xy-18xy'

Step4)(3x²y)(15x²+2xy-24y²)=(3x²y)(15x²+20xy-18xy-24y²)

=(3x²y){5x(3x+4y)-6y(3x+4y)}

taking out 3x+4y as common we get

=(3x²y){(3x+4y)(5x-6y)}

=(3x²y)(3x+4y)(5x-6y)

hence,45x⁴y+6x³y²-72y³x²=(3x²y)(3x+4y)(5x-6y)

Second method:-

Simply explit the second term of the given equation

45x⁴y+6x³y²-72y³x³y=45x⁴y+60x³y²

-54x³y²-72y³x²

=15x³y(3x+4y)-18x²y²(3x+4y)

=(15x³y-18x²y²)(3x+4y)

=(3x²y)(3x+4y)(5x-6y)

Answered by SyedNomanShah
56

Refer to the attachment.

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