Question

46 42 35 21 46 39 59 46 38 31 फाइंड द मीडियन एंड रिमोट​

Answer 1

Step-by-step explanation:

median of this data is 39 and 42

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Answer 2

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MEDIAN:

First we have to arrange the numbers in ascending order.

AO: 21 31 35 38 39 42 46 46 46 59

$median=\frac{n}{2} and \: \frac{n}{2}+1 \: \: \: \\ (if \: the \: number \: of \: observations \: are \: even) \\ \\ median = \frac{n + 1}{2} \\ (if \: the \: number \: of \: observations \: are \: odd)$

As the number of observations (n)are 10. So we have to use first formula

$\frac{n}{2} = \frac{10}{2} = 5 th \: term\\ \frac{n}{2} + 1 = 5 \: + 1 = 6th \: term$

average of 5th and 6th term = median

$\frac{39 + 42}{2} = 81 \div 2 = 40.5$

Therefore, median = 40.5

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Mode:

mode= 46, as it's frequency is 3, and leftover numbers frequency is 1.

Frequency refers to the number of times an event or a value occurs.

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Mean:

$\frac{sum \: of \: the \: observations}{number \: of \: observations} = mean$

$\frac{403}{10} = 40.3$

Therefore, mean= 40.3

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