Question

46. A, B and C can do a work in 20 days, 30 days and 40 days
respectively, each of them work for one day alternatively in
same order, then in how many days work would be completed?
16 days
(b) 18 % days
(c) 25% days (d) 27 days​

Answer 1

Answer:

First day A+B works=2+3=5 units ,

2nd day A+C works=2+6=8 units

3rd dayA+B works=5 units

In one cycle work is completed = 13 units

It will continue at last, work will finish in

6013(8+5)= 4 cycle and 8 units of work is left.

Now, A will do with 'B' and they will complete 5 units.

Remaining 3 units will be done by A and C in

Total time = 4 cycle×2=8 days

(A+B)=1 days

A+C=38days

Hence, total time

= 8days+(A+B)′s days+(A+C)′s days

=8+1+38=938 days

Answer 2

Answer:

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