Question

46.a. Calculate the standard enthalpy of formation of CH3OH(l) from the following data: (2) i. CH3OH (l) + 3/2 O2(g) → CO2(g) + 2H2O(l) ; ∆rH0 = – 726 kJ mol–1 ii. C(graphite) + O2(g) → CO2(g) ; ∆cH0 = – 393 kJ mol–1 iii. H2(g) + ½ O2(g) → H2O(l) ; ∆fH0 = – 286 kJ mol–1. b. Calculate the lattice enthalpy of NaCl from the following data: (3) i. Standard enthalpy of sublimation of sodium metal is 108.4 KJ/mol ii. First ionization enthalpy of sodium atom is 496 KJ/mol iii. Bond dissociation of Cl2 molecule is 242 KJ/mol iv. Electron gain enthalpy of chlorin atom is – 348.6 KJ/mol v. Standard enthalpy of formation of NaCl is – 411.2 KJ/mol
OR
a. Calculate enthalpy change for the reaction H2 + Br2  2HBr. Given the bond enthalpies of H2, Br2 and HBr are 435kJ/mol, 192kJmol and 369 kJ/mol respectively. (2) ΔH0 = ??? b. Calculate the enthalpy change for the process, CCl4(g) �⎯ ⎯ � C(g) + 4 Cl(g) and calculate bond enthalpy of C – Cl in CCl4(g). (3) ΔVAPH0 (CCL4) = 30.5 KJ mol–1. ΔfH0 (CCL4) = –135.5 KJ mol–1. ΔaH0 (C) = 715.0 KJ mol–1. ΔaH0 (CL2) = 242 KJ mol–1​

Answer 1

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