Question

46. A total of 1100 votes were polled in a school elec-
tion for a school head boy. Among three contes-
tants, the first secured 25% votes more than the
second and the third secured 300 votes less than
the first. By what per cent of votes was the third
contestant defeated by the first contestant?​

Answer 1

Answer:

Step-by-step explanation:

given number of votes=1100

let the second scored x votes

the first scored =x+25%x=125x/100=5x/4

third=5x/4-300

x+5x/4+5x/4-300=1100

x+10x/4=1400

14x/4=1400

x=400

so the second scored 400 votes

first scored=5*400/4=500

third=200

percentage=200/500*100=40%

Answer 2

Answer:

Let second contestant secured 'x' no. of votes

therefore,first secured 'x +25x/100'

& third secured 'x +25x/100-300'

As per given condition

(x+ 25x/100)+(x) +(x+25x/100-300)=1100

(100x+25x/100)+(x)+(100x+25x/100-300)=1100

125x/100+x+125x/100=1100+300

125x+125x/100+x=1400

250x/100+x=1400

250x+100x/100=1400

350x=1400×100

x=140000/350

x=400

First secured 400+25 (400)/100=500

&

Third secured 400+25(400)/100-300=200

Defeat percent of third contestant with first percent is =100×200/500=40%

Answer= 40%