Question

46.
Find out the least number which when divided by 9, 12, 16 and 30 leaves a remainder of 3
in each case​

Answer 1

Take the LCM of 9, 12, 16 and 30.

LCM ( 9, 12, 16, 30 ) = 720.

720 is the least no. that can divide these no. leaving remainder 0.

We have to find out the number that divides leaving remainder 3 in each case.

So, we add 3 to 720.

➡ 720 + 3 = 723.

Required no is 723.

Let's check this number.

➡ 723 ÷ 9 => q = 80 and r = 3

➡ 723 ÷ 12 => q = 60 and r = 3

➡ 723 ÷ 16 => q = 45 and r = 3

➡ 723 ÷ 30 => q = 24 and = r = 3

Hope it will help u !!