Question

46. Following is the frequency distribution table showing the ages of 100 students
who had joined 'Sanskar Camp'. Find the mean of the ages.
Age (years) Frequency
8.0
20
10.5
30
12.0
25
3055
7.0
25​

Answer 1

Answer:

Where is the frequency

Answer 2

MEAN= TOTAL NO. OF OBSERVATION

______________________________

SUM OF OBSERVATION

MEAN=

$\frac{8.0 + 20 + 10.5 + 30 + 12.0 + 25 + 3055 + 7</em></strong><strong><em>.</em></strong><strong><em>0 + 25}{9}$

=

$\frac{</em></strong><strong><em>3192</em></strong><strong><em>.5}{9}$

=

$</em></strong><strong><em>354</em></strong><strong><em>.72(approx)$

THIS IS YOUR MEANN....

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