Question

46. For what value of k will the consecutive terms 2k + 1, 3k + 3 and 5k - 1 form an
A.P.?
[Foreign
Sol. Given that 2k + 1, 3k + 3 and 5k - 1 are in A.P.
So
(3k + 3 - (2k + 1) = (5k-1 - (3k + 3)​

Answer 1

Step-by-step explanation:

here u go

hope you understand....

Answer 2

Answer:

2k+1

3k+3

5k-1

=3k

6k

-4k

9k-4k

final answer=4k