Question

46 gram ethanol is present in 36 gram of water. Calculate mole fraction of each component

Answer 1

Answer:

Explanation:

No. of mol of C2H5OH = 46g/46g/mol

= 1mol

No. of mol of water = 36g/18g/mol

= 2mol

Mole fraction of water = 1/3

Mole fraction of ethyl alcohol = 2/3

Answer 2

Answer:-

• Mole fraction of ethanol = 0.33

• Mole fraction of water = 0.67

Explanation:-

• Molar mass of Carbon (C) = 12g/mol

• Molar mass of Hydrogen (H) = 1g/mol

• Molar mass of Oxygen (O) = 16g/mol

Hence, molar mass of ethanol [C2H5OH] :-

= 12×2+1×5+16+1

= 24+5+17

= 46g/mol

Molar mass of water [H2O] :-

= 1×2+16

= 18g/mol

Number of moles in 46g of ethanol :-

= Given Mass/Molar mass

= 46/46

= 1 mole

Number of moles in 36g of water :-

= Given Mass/Molar mass

= 36/18

= 2 mole

Mole fraction of ethanol :-

= Mole of ethanol/Total mole in solution

= 1/[1+2]

= 1/3

= 0.33

Mole fraction of water :-

= Mole of water/Total mole in solution

= 2/[1+2]

= 2/3

= 0.67