Question

46.
If f(x)=ఎక్స్ స్క్వేర్2* log x(x>0), then find f'(x).​

Answer 1

Answer:

x ( 1 + 2 log x )

Step-by-step explanation:

f(x) = x^2 log x

f'(x) = (x^2)' log x + x^2 (log x)'

= 2x logx + x^2/x

= 2x log x + x

= x ( 1 + 2 log x )

Note : product rule is applied