Math, asked by pushpanjalipatel978, 3 months ago

46. Ishan left his home by car at 7:00 AM for Durgapur. At 7:30 AM, he overtook a truck also travelling towards Durgapur. He reached Durgapur and started his journey back home after two hours. One hour after leaving Durgapur he crossed the same truck. Find the ratio of speed of Ishan's car and the truck, if he crossed the truck for the second time at 1:00 PM (assume truck did not halt during the journey and both the car and truck travelled with constant speeds). (a) 9:4 (b) 11:3 (c) 13:7 (d) 5:3 ​

Answers

Answered by ashish2473
4

Answe

Step-by-step explanation:

Answered by sakshambhati
5

Answer:

11:3

Step-by-step explanation:

let dist. = d

from ques it can be inferred that ishan reached Durgapur at 10 am. hence, 1 hr dist. = d/3 1/2 hr dist. = d/6 ....(1)

Truck travelled from 7:30 to 1 pm = 5.5 hrs

Ishan travelled for 4 hrs (3+1) and dist. of d+d/3

Truck travelled 1-(d/3+d/6) = d/2 // draw diagram and refer to eq 1, you will get it.

ratio = ( 4/3d ÷4 ) ÷ ( 0.5d ÷ 5.5 ) = 11:3

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