Question

46. One of the roots of quadratic equation
x2 - (√3 +1)x+ √3 = 0 is
(1)1/√3
(2) √3+1
(4) √3
(3) 2√3​

Answer 1

$\mathcal{\red{\huge{Heyamate}}}$

✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶

$\mathcal{\green{\huge{Answer}}}$

The correct option is (4)- _/3

Explanation:-

${x}^{2} - ( \sqrt{3} + 1)x + \sqrt{3} \\ {x}^{2} - \sqrt{3} x - x + \sqrt{3} \\ x(x - \sqrt{3} ) - 1(x - \sqrt{3} ) \\ (x - 1)(x - \sqrt{3} ) \\ so \\ x = 1 \: and \: \sqrt{3}$

✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶

$\mathcal{\red{\huge {Hope\:it\:helps}}}$

⍖━━━━━━━━━━⍖

$\mathbb{\huge{\blue{R-K}}}$

$\mathcal{\huge{\green{Plz_-Follow_-Me}}}$