46. Schaj Batra gets pocket money from his father ev
day. Out of the pocket money, he saves money
poor people in his locality. On Ist day he saves 275
On each succeeding day he increases his saving by
2.5. Find
(i) the amount saved by Sehaj on 10th day.
(ii) the amount saved by Sehaj on 25th day, and
(iii) the total amount saved by Sehaj in 30 days.
Answers
Answered by
2
Answer:
10th day = 3000 25th day = 6937.5 30 days = 9937.5
Step-by-step explanation:
275×10.+2.5×10=3000 . 275×25+2.5×25=6937.5. Total=9937.5
Answered by
5
Answer:-
i. Money saved on 1st day = Rs. 27.5
Sehaj increases his saving by a fixed amount of Rs. 2.5 .'. His saving form an AP with a = 27.5 and l = 2.5
..Money saved on 10th day,
= 27.5 + 22.5 = Rs. 50
ii. a25 = a = 24d
= 27.5 24(2.5)
= 27.5 + 60 = Rs. 87.5
iii. Total amount saved by Sehaj in 30 days.
302 x 27.5+ (30- 1) × 2.5]
= 15(55+29(2.5)
= Rs. 1912.5
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